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If A takes half as long to do a piece of work as B takes and if C does it in the same time as A and B together and if all three working together would take 7 days, then how long would each take separately?Marks : 2Negative Marks : 0Answer here21, 42, 1414, 35, 2114, 42, 4942, 35, 49

Question

If A takes half as long to do a piece of work as B takes and if C does it in the same time as A and B together and if all three working together would take 7 days, then how long would each take separately?Marks : 2Negative Marks : 0Answer here21, 42, 1414, 35, 2114, 42, 4942, 35, 49

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Solution

Let's denote the amount of work as W.

  1. If A takes half as long to do a piece of work as B takes, then A does twice as much work in the same time as B. So, if B does W in b days, A does W in a = b/2 days.

  2. If C does it in the same time as A and B together, then C does W in c = a + b days.

  3. If all three working together would take 7 days, then 1/a + 1/b + 1/c = 1/7.

Substituting a = b/2 and c = a + b into the equation, we get 2/b + 1/b + 1/(b + 2b/2) = 1/7, which simplifies to 3/b + 1/(3b/2) = 1/7.

Solving this equation for b, we get b = 14 days. Then a = b/2 = 7 days and c = a + b = 21 days.

So, A would take 7 days, B would take 14 days, and C would take 21 days to do the work separately.

This problem has been solved

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