The distance between places A and B is 999 km. An express train leaves place A at 6 am and runs at a speed of 55.5 km/hr. The train stops on the way for 1 hours 20 minutes. It reaches B at?Options11:00 PM12:00 PM1.20 AM6 PM
Question
The distance between places A and B is 999 km. An express train leaves place A at 6 am and runs at a speed of 55.5 km/hr. The train stops on the way for 1 hours 20 minutes. It reaches B at?Options11:00 PM12:00 PM1.20 AM6 PM
Solution
To solve this problem, we need to calculate the total time the train takes to travel from place A to place B.
Step 1: Calculate the travel time The distance between A and B is 999 km and the speed of the train is 55.5 km/hr. So, the time taken to cover the distance is given by the formula:
Time = Distance/Speed
Substituting the given values, we get:
Time = 999 km / 55.5 km/hr = 18 hours
Step 2: Add the stoppage time The train stops for 1 hour and 20 minutes. We need to convert this time into hours to add it to the travel time. 20 minutes is 1/3 of an hour, so the stoppage time is 1.33 hours.
Total time = Travel time + Stoppage time = 18 hours + 1.33 hours = 19.33 hours
Step 3: Calculate the arrival time The train leaves at 6 am. Adding the total time of 19.33 hours to this, we get the arrival time.
6 am + 19 hours = 1 am (next day) 1 am + 0.33 hours = 1:20 am (next day)
So, the train reaches place B at 1:20 am. The correct option is 1.20 AM.
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