Knowee
Questions
Features
Study Tools

Question 1. Graph each function, not by plotting points, but by starting with the graph of one of the standard functions?(Hint: First sketch the basic standard function and then show how it changes by shifting, compressing/stretching orreflection) (20 Point)a) ๐’š = ๐Ÿ|๐’™ + ๐Ÿ| โˆ’ ๐Ÿb) ๐ฒ = โˆš๐’™ โˆ’ ๐Ÿ๐Ÿ‘ + ๐ŸQuestion 2. Determine whether the graph of the functions below are symmetric about the y-axis, the origin, orneither?(20 Points)a) ๐’š = ๐’™ โˆ’ ๐’”๐’Š๐’๐’™b) ๐’š = ๐’™๐Ÿ’ โˆ’ ๐’™๐Ÿ โˆ’ ๐Ÿ‘Question 3. Find the following limits? (30 Points)a) ๐‘™๐‘–๐‘š๐‘ฅโ†’44๐‘ฅโˆ’๐‘ฅ22โˆ’โˆš๐‘ฅb) ๐‘™๐‘–๐‘š๐‘ฅโ†’0tan 3๐‘ฅsin 8๐‘ฅc) ๐‘™๐‘–๐‘š๐‘ฅโ†’โˆž9๐‘ฅ4+ ๐‘ฅ3๐‘ฅ4โˆ’5๐‘ฅ2+๐‘ฅโˆ’2Question 4. Find Horizontal asymptotes of the Function below, and determine the behaviour of the function around theasymptotes?(30 Points)๐’‡(๐’™) = ๐’™ + ๐Ÿ๐’™๐Ÿ โˆ’ ๐Ÿ

Question

Question 1. Graph each function, not by plotting points, but by starting with the graph of one of the standard functions?(Hint: First sketch the basic standard function and then show how it changes by shifting, compressing/stretching orreflection) (20 Point)a) ๐’š = ๐Ÿ|๐’™ + ๐Ÿ| โˆ’ ๐Ÿb) ๐ฒ = โˆš๐’™ โˆ’ ๐Ÿ๐Ÿ‘ + ๐ŸQuestion 2. Determine whether the graph of the functions below are symmetric about the y-axis, the origin, orneither?(20 Points)a) ๐’š = ๐’™ โˆ’ ๐’”๐’Š๐’๐’™b) ๐’š = ๐’™๐Ÿ’ โˆ’ ๐’™๐Ÿ โˆ’ ๐Ÿ‘Question 3. Find the following limits? (30 Points)a) ๐‘™๐‘–๐‘š๐‘ฅโ†’44๐‘ฅโˆ’๐‘ฅ22โˆ’โˆš๐‘ฅb) ๐‘™๐‘–๐‘š๐‘ฅโ†’0tan 3๐‘ฅsin 8๐‘ฅc) ๐‘™๐‘–๐‘š๐‘ฅโ†’โˆž9๐‘ฅ4+ ๐‘ฅ3๐‘ฅ4โˆ’5๐‘ฅ2+๐‘ฅโˆ’2Question 4. Find Horizontal asymptotes of the Function below, and determine the behaviour of the function around theasymptotes?(30 Points)๐’‡(๐’™) = ๐’™ + ๐Ÿ๐’™๐Ÿ โˆ’ ๐Ÿ

...expand
๐Ÿง Not the exact question you are looking for?Go ask a question

Solution

Question 1: a) The standard function here is y = |x|. The graph of y = |x| is a V shape with the point at the origin (0,0). The function y = 2|x + 2| - 1 is a transformation of the standard function. It shifts the graph 2 units to the left and 1 unit down. The 2 in front of the absolute value stretches the graph vertically by a factor of 2.

b) The standard function here is y = โˆšx. The graph of y = โˆšx is a half parabola lying on its side. The function y = โˆš(x - 13) + 1 is a transformation of the standard function. It shifts the graph 13 units to the right and 1 unit up.

Question 2: a) The function y = x - sinx is not symmetric about the y-axis or the origin. You can test this by replacing x with -x and seeing if the equation remains the same (symmetry about the y-axis) or changes sign (symmetry about the origin). Neither happens in this case.

b) The function y = x^4 - x^2 - 3 is symmetric about the y-axis. Replacing x with -x gives the same equation.

Question 3: a) The limit as x approaches 4 of (4x - x^2) / (2 - โˆšx) can be found by direct substitution, giving (16 - 16) / (2 - 2) = 0/0, which is an indeterminate form. You would need to use L'Hopital's rule or some algebraic manipulation to find the limit.

b) The limit as x approaches 0 of tan(3x) / sin(8x) can be found using L'Hopital's rule or by noting that as x approaches 0, both tan(3x) and sin(8x) approach 0, so the limit is 0/0, another indeterminate form.

c) The limit as x approaches infinity of (9x^4 + x^3) / (x^4 - 5x^2 + x - 2) can be found by dividing every term by x^4, the highest power of x in the denominator, and then taking the limit as x approaches infinity, giving 9 + 0 / 1 - 0 + 0 - 0 = 9.

Question 4: The horizontal asymptotes of the function f(x) = (x + 1) / (x^2 - 1) can be found by looking at the degrees of the numerator and denominator. Since the degree of the denominator is higher, the horizontal asymptote is y = 0. As x approaches infinity, the function approaches 0 from above, and as x approaches negative infinity, the function approaches 0 from below.

This problem has been solved

Similar Questions

How does the graph of ๐‘“(๐‘ฅ)=โˆ’32๐‘ฅโˆ’4f(x)=โˆ’3 2x โˆ’4 differ from the graph of ๐‘”(๐‘ฅ)=โˆ’32๐‘ฅg(x)=โˆ’3 2x ?A.The graph of ๐‘“(๐‘ฅ)f(x) is shifted four units to the right of the graph of ๐‘”(๐‘ฅ)g(x).B.The graph of ๐‘“(๐‘ฅ)f(x) is shifted four units down from the graph of ๐‘”(๐‘ฅ)g(x).C.The graph of ๐‘“(๐‘ฅ)f(x) is shifted four units up from the graph of ๐‘”(๐‘ฅ)g(x).D.The graph of ๐‘“(๐‘ฅ)f(x) is shifted four units to the left of the graph of ๐‘”(๐‘ฅ)g(x).SUBMITarrow_backPREVIOUS

QUESTION 1The diagram below shows the functions of and๐‘“(๐‘ฅ) =โˆ’ 2๐‘ฅ2 + 5๐‘ฅ + 3. is the turning point of and and are the๐‘”(๐‘ฅ) = 2๐‘ฅ + 1 ๐ถ ๐‘“(๐‘ฅ), ๐ด ๐ธintercepts of . and are points on both graphs and . cuts๐‘ฅ โˆ’ ๐‘“(๐‘ฅ) ๐ท ๐ด ๐‘“(๐‘ฅ) ๐‘”(๐‘ฅ) ๐‘“(๐‘ฅ)the axis at and cuts the axis at .๐‘ฆ โˆ’ ๐ต ๐‘”(๐‘ฅ) ๐‘ฆ โˆ’ ๐ผFigure 1: Diagram for Question 1.4Use the information and diagram above and:1.1 Calculate the length of:1.1.1 ๐ด๐ธ (4)1.1.2 ๐ต๐‘‚ (2)1.1.3 ๐‘‚๐น (3)1.1.4 ๐ถ๐น (3)1.1.5 ๐ต๐ผ (2)1.2 Determine the coordinates of .๐ท (6)1.3 Write down the values of for which .๐‘ฅ ๐‘“(๐‘ฅ) < ๐‘”(๐‘ฅ) (2)1.4 Write down in the form using completing๐‘“(๐‘ฅ) ๐‘“(๐‘ฅ) = ๐‘Ž(๐‘ฅ โˆ’ ๐‘)2 + ๐‘ž,the square. (4)1.5 Write down the domain of .๐‘“(๐‘ฅ) (1)1.6 Write down the range of .๐‘”(๐‘ฅ) (1)[28

The graphs of f and g are given. Use them to evaluate each limit, if it exists. (If an answer does not exist, enter DNE.)The x y coordinate plane is given. There is one curve and one point on the graph. The point occurs at (โˆ’1, 3). The curve enters the window at (โˆ’2, โˆ’1), goes up and right, passes through the open point (โˆ’1, 1), changes direction at (0, 2), goes down and right, and passes through the open point (2, โˆ’1). At this point, the curve turns sharply forming a cusp, goes up and right, and exits the window at (4, 2). The x y coordinate plane is given. There are two curves on the graph. The first curve enters the window at (โˆ’2, 0), goes up and right, and ends at the closed point (0, 3). The second curve begins at the open point (0, 1), goes up and right, and passes through (2, 2). At this point, the curve turns sharply forming a cusp, goes down and right traveling in a straight line, and exits the window at (4, โˆ’2).(a)limย xโ†’2ย [f(x) + g(x)](b)limย xโ†’0ย [f(x) โˆ’ g(x)](c)limย xโ†’โˆ’1ย [f(x)g(x)](d)limย xโ†’3ย f(x)g(x)(e)limย xโ†’2ย [x2f(x)](f)f(โˆ’1) +ย limย xโ†’โˆ’1ย g(x)

Instructions: Determine whether graphs of each of the exponential functions would show vertical stretch or vertical compression and whether there is reflection over the x๐‘ฅ-axis.y=โˆ’2(3)x๐‘ฆ=โˆ’2(3)๐‘ฅVertical Answer 1 Question 14Reflection over the x๐‘ฅ-axis? Answer 2 Question 14

For the function f whose graph is shown, state the following. (If the limit is infinite, enter 'โˆž' or '-โˆž', as appropriate. If the limit does not otherwise exist, enter DNE.)FigureThe x y coordinate plane is given. Refer to the adjacent description for more details.Description(a)limย x โ†’ โˆ’7ย f(x)(0,2) (b)limย x โ†’ โˆ’3ย f(x)DNE (c)limย x โ†’ 0ย f(x)2 (d)limย x โ†’ 6โˆ’ย f(x)โˆž (e)limย x โ†’ 6+ย f(x)โˆ’โˆž (f)the equations of the vertical asymptotes (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)x = (โˆ’3,6)

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.