Write the quadratic equation in standard form:minus, 22, equals, x, minus, 5, minus, 4, x, squared−22=x−5−4x 2
Question
Write the quadratic equation in standard form:minus, 22, equals, x, minus, 5, minus, 4, x, squared−22=x−5−4x 2
Solution
The given equation is -22 = x - 5 - 4x^2.
To write this in standard form, we need to rearrange the terms so that the equation is in the form ax^2 + bx + c = 0.
First, let's move the x^2 term to the left side of the equation by adding 4x^2 to both sides:
4x^2 - 22 = x - 5
Next, let's move the x term to the left side by subtracting x from both sides:
4x^2 - x - 22 = -5
Finally, let's move the constant term to the left side by adding 5 to both sides:
4x^2 - x - 17 = 0
So, the quadratic equation in standard form is 4x^2 - x - 17 = 0.
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