The length of a rectangle is five times its width.If the area of the rectangle is 320 ft2, find its perimeter.
Question
The length of a rectangle is five times its width.If the area of the rectangle is 320 ft2, find its perimeter.
Solution
Sure, let's solve this step by step.
Step 1: Let's denote the width of the rectangle as x. Therefore, the length of the rectangle is 5x.
Step 2: The area of a rectangle is calculated by multiplying its length by its width. So, we can set up the equation: x * 5x = 320 ft².
Step 3: Simplify the equation to 5x² = 320.
Step 4: Divide both sides of the equation by 5 to solve for x². x² = 320/5 = 64.
Step 5: Take the square root of both sides to solve for x. x = √64 = 8 ft.
Step 6: Now that we know the width (x), we can find the length by multiplying the width by 5. So, the length is 5 * 8 = 40 ft.
Step 7: The perimeter of a rectangle is calculated by adding up all its sides. So, the perimeter is 2*(length + width) = 2*(40 ft + 8 ft) = 96 ft.
So, the perimeter of the rectangle is 96 ft.
Similar Questions
-The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?
The length of a rectangle is five times its width.If the perimeter of the rectangle is 96 m, find its area.
The length of a rectangle is twice its width.If the perimeter of the rectangle is 54 yd, find its area.
The perimeter of a rectangle is 5555 feet. If the length is 1414 feet, find the width.Step 3 of 3: Finally, solve the problem by substituting in the appropriate values. (Round your answer to 2 decimal places if necessary.)
The perimeter of a rectangle is 4646 feet. If the length is 1212 feet, find the width.Step 3 of 3: Finally, solve the problem by substituting in the appropriate values. (Round your answer to 2 decimal places if necessary.)
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.