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Select the correct answerThe digit at the unit’s place of a two-digit number is increased by 50%. And the digit at the ten’s place of the same number is increased by 100%. Now, we find the new numbers is 33 more than original number. Find the original number.Options3562636436

Question

Select the correct answerThe digit at the unit’s place of a two-digit number is increased by 50%. And the digit at the ten’s place of the same number is increased by 100%. Now, we find the new numbers is 33 more than original number. Find the original number.Options3562636436

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Solution

The problem can be solved by using the concept of place values in a two-digit number.

Let's denote the unit's digit as 'u' and the ten's digit as 't'. The original number can be represented as 10t + u.

According to the problem, the unit's digit is increased by 50% and the ten's digit is increased by 100%. So, the new number becomes 10(2t) + 1.5u.

The problem states that the new number is 33 more than the original number. So, we can set up the following equation:

10(2t) + 1.5u = 10t + u + 33

Solving this equation gives us:

20t + 1.5u = 10t + u + 33

10t + 0.5u = 33

We can see that 't' and 'u' must be integers because they represent digits. The only option that satisfies this equation is t=3 and u=6.

So, the original number is 36.

This problem has been solved

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