A 500g model rocket with a weight of 4.9N is launched straight up. The small rocket motor burns for 5s and has a steady thrust of 20N, What altitude does the rocket reach when it runs out of fuel? Hint: Start by considering net thrust of the rocket A. 377m B.408m C.396m D.366m
Question
A 500g model rocket with a weight of 4.9N is launched straight up. The small rocket motor burns for 5s and has a steady thrust of 20N, What altitude does the rocket reach when it runs out of fuel? Hint: Start by considering net thrust of the rocket A. 377m B.408m C.396m D.366m
Solution
Step 1: Calculate the net force acting on the rocket. The net force is the difference between the upward force (thrust) and the downward force (weight).
Net Force = Thrust - Weight = 20N - 4.9N = 15.1N
Step 2: Use Newton's second law (F = ma) to calculate the acceleration of the rocket. The mass of the rocket is 500g or 0.5kg (since 1g = 0.001kg).
Acceleration = Net Force / Mass = 15.1N / 0.5kg = 30.2 m/s²
Step 3: Use the kinematic equation (d = vit + 0.5at²) to calculate the distance the rocket travels while the engine is burning. The initial velocity (vi) is 0 (since the rocket starts from rest), the acceleration (a) is 30.2 m/s², and the time (t) is 5s.
Distance = 05 + 0.530.25² = 0 + 0.530.2*25 = 0 + 378.5m
So, the rocket reaches an altitude of approximately 378.5m when it runs out of fuel. The closest answer is A. 377m.
Similar Questions
A test rocket is fired straight up from rest with a net acceleration of 20.0 m/s2.After 4.00 seconds the motor turns off, but the rocket continues to coast upward.What maximum elevation does the rocket reach?Neglect air friction and express your answer in meters.
A 9.5 kg test rocket is fired vertically from Cape Canaveral. Its fuel gives it a kinetic energy of 1915 J by the time the rocket engine burns all of the fuel. What additional height will the rocket rise? Assume that air resistance is negligible.
A 5 kg model rocket is lifted off the ground by a force of 80 N. At a height of 10 m, what is the speed of the rocket? Use g = 10 m/s2Question 1Answera.17.89 m/sb.14.76 m/sc.21.99 m/sd.10.95 m/se.35.9 m/s
A model rocket is launched from the deck in Jim’s backyard and the path followed by the rocket can bemodelled by the relation ℎ = −5% ! + 100% + 15, where ℎ, in meters, is the height that the model rocket reachesafter % seconds.a) What is the height of the deck?
At a certain instant of time the mass of a rocket going up vertically is 100 kg. If it is ejecting 5 kg of gas per second at a speed of 400 m/s, the acceleration of the rocket is find the value of x ?(take g = 10 )A 3 B 5 C 10 D 8
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.