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Convert the Bearing direction N 430 07’ W into decimal Azimuth format (write only the numeric answer with 3 decimals and no units)

Question

Convert the Bearing direction N 430 07’ W into decimal Azimuth format (write only the numeric answer with 3 decimals and no units)

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Solution

The bearing direction N 43° 07' W can be converted into decimal azimuth format by following these steps:

  1. Identify the quadrant: In this case, the direction is North West (N...W), which is the fourth quadrant.

  2. Convert the degrees, minutes, and seconds to decimal degrees:

    • The given bearing is 43 degrees and 07 minutes.
    • To convert minutes to degrees, divide the number of minutes by 60.
    • So, 07' = 07/60 = 0.117 degrees.
  3. Add the decimal degrees to the whole degrees:

    • So, 43 + 0.117 = 43.117 degrees.
  4. Convert the bearing to azimuth:

    • In the fourth quadrant (N...W), the azimuth = 360 - bearing.
    • So, the azimuth = 360 - 43.117 = 316.883 degrees.

So, the bearing direction N 43° 07' W in decimal azimuth format is 316.883.

This problem has been solved

Similar Questions

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To find the component form of the vector \(\mathbf{v}\) with a magnitude of 4 and a bearing of 125°, we need to convert the polar coordinates (magnitude and direction) into Cartesian coordinates (components along the \(i\) and \(j\) directions). 1. **Convert the bearing to a standard angle:** Bearings are measured clockwise from the north direction. A bearing of 125° means the angle is 125° clockwise from the north. To convert this to a standard angle (measured counterclockwise from the positive x-axis), we use: \[ \text{Standard angle} = 360° - 125° = 235° \] 2. **Calculate the components:** The components of the vector can be found using trigonometry: \[ v_x = v \cos(\theta) \] \[ v_y = v \sin(\theta) \] where \(v\) is the magnitude and \(\theta\) is the standard angle. Given: \[ v = 4, \quad \theta = 235° \] Converting 235° to radians: \[ \theta = 235° \times \frac{\pi}{180°} = \frac{235\pi}{180} \approx 4.1015 \text{ radians} \] Now, calculate the components: \[ v_x = 4 \cos(235°) = 4 \cos(4.1015) \approx 4 \times (-0.5736) \approx -2.29 \] \[ v_y = 4 \sin(235°) = 4 \sin(4.1015) \approx 4 \times (-0.8192) \approx -3.28 \] 3. **Write the vector in component form:** \[ \mathbf{v} = v_x \mathbf{i} + v_y \mathbf{j} = -2.29\mathbf{i} - 3.28\mathbf{j} \] Therefore, the correct answer is: \[ \boxed{E} \]

If you measure an Azimuth of 213.2 with a magnetic compass, and the Magnetic Declination of your location is 7.2 degrees East, what is the True Azimuth (report in numerical DD format, with no units)

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