This problem can be solved using Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant. In mathematical terms, P1*V1 = P2*V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Step 1: Identify the knowns.
P1 = 1.00 atm (initial pressure)
V1 = 400.0 mL (initial volume)
V2 = 2.0 L (final volume)

Step 2: Convert all volumes to the same units.
1 L = 1000 mL, so V2 = 2.0 L = 2000 mL

Step 3: Substitute the known values into Boyle's Law and solve for P2 (final pressure).
P1*V1 = P2*V2
1.00 atm * 400.0 mL = P2 * 2000 mL
P2 = (1.00 atm * 400.0 mL) / 2000 mL
P2 = 0.20 atm

So, the pressure at which the volume of the gas is 2.0 L is 0.20 atm.

Question

This problem can be solved using Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant. In mathematical terms, P1*V1 = P2*V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Step 1: Identify the knowns. 
P1 = 1.00 atm (initial pressure)
V1 = 400.0 mL (initial volume)
V2 = 2.0 L (final volume)

Step 2: Convert all volumes to the same units. 
1 L = 1000 mL, so V2 = 2.0 L = 2000 mL

Step 3: Substitute the known values into Boyle's Law and solve for P2 (final pressure).
P1*V1 = P2*V2
1.00 atm * 400.0 mL = P2 * 2000 mL
P2 = (1.00 atm * 400.0 mL) / 2000 mL
P2 = 0.20 atm

So, the pressure at which the volume of the gas is 2.0 L is 0.20 atm.

Knowee AI · Accepted Answer

This problem can be solved using Boyle's Law, which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant. In mathematical terms, P1*V1 = P2*V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

Step 1: Identify the knowns. 
P1 = 1.00 atm (initial pressure)
V1 = 400.0 mL (initial volume)
V2 = 2.0 L (final volume)

Step 2: Convert all volumes to the same units. 
1 L = 1000 mL, so V2 = 2.0 L = 2000 mL

Step 3: Substitute the known values into Boyle's Law and solve for P2 (final pressure).
P1*V1 = P2*V2
1.00 atm * 400.0 mL = P2 * 2000 mL
P2 = (1.00 atm * 400.0 mL) / 2000 mL
P2 = 0.20 atm

So, the pressure at which the volume of the gas is 2.0 L is 0.20 atm.

The volume of a gas is 400.0 mL when the pressure is 1.00 atm. At the same temperature, what is the pressure at which the volume of the gas is 2.0 L?

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