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Consider the following transactions with data items P and Q initialized to zero:T1: read (P) ;read (Q) ;if P = 0 then Q : = Q + 1 ;write (Q) ;T2: read (Q) ;read (P) ;if Q = 0 then P : = P + 1 ;write (P) ;Any non-serial interleaving of T1 and T2 for concurrent execution leads to

Question

Consider the following transactions with data items P and Q initialized to zero:T1: read (P) ;read (Q) ;if P = 0 then Q : = Q + 1 ;write (Q) ;T2: read (Q) ;read (P) ;if Q = 0 then P : = P + 1 ;write (P) ;Any non-serial interleaving of T1 and T2 for concurrent execution leads to

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Solution 1

The given transactions T1 and T2 are reading and modifying the data items P and Q. The transactions are designed in such a way that if one data item is zero, the other is incremented.

Let's consider a non-serial interleaving of T1 and T2:

  1. T1: read(P) - P is 0
  2. T2: read(Q) - Q is 0
  3. T1: read(Q) - Q is 0
  4. T2: read(P) - P is 0
  5. T1: if P=0 then Q:=Q+1 - Q becomes 1
  6. T2: if Q=0 then P:=P+1 - this condition is not met as Q is 1, so P remains 0
  7. T1: write(Q) - Q is written as 1
  8. T2: write(P) - P is written as 0

So, the final values of P and Q are 0 and 1 respectively.

If we consider any other non-serial interleaving, the final values of P and Q will be the same because of the conditions in the transactions. If P is 0, Q is incremented and if Q is 0, P is incremented. Since they are initialized to zero, in any interleaving, one of them will be incremented while the other remains zero.

Therefore, any non-serial interleaving of T1 and T2 for concurrent execution leads to a final state where one of the data items is 1 and the other is 0.

This problem has been solved

Solution 2

The question is asking about the possible outcomes of non-serial (concurrent) execution of two transactions T1 and T2.

Let's break down the transactions:

T1:

  1. Read P
  2. Read Q
  3. If P = 0, then increment Q by 1
  4. Write Q

T2:

  1. Read Q
  2. Read P
  3. If Q = 0, then increment P by 1
  4. Write P

Both P and Q are initialized to zero.

Let's consider a non-serial interleaving of T1 and T2:

  1. T1 reads P (P=0)
  2. T1 reads Q (Q=0)
  3. T1 checks if P=0, it is, so it increments Q by 1 (Q=1)
  4. T2 reads Q (Q=1)
  5. T2 reads P (P=0)
  6. T2 checks if Q=0, it's not, so it does nothing
  7. T1 writes Q (Q=1)
  8. T2 writes P (P=0)

So, in this non-serial interleaving, P remains 0 and Q becomes 1.

However, the question is asking about any non-serial interleaving. This means we have to consider all possible orderings of the operations in T1 and T2.

In some orderings, T2 might execute before T1 has a chance to increment Q, in which case P would be incremented by T2.

So, the final values of P and Q can vary depending on the specific non-serial interleaving of T1 and T2.

This problem has been solved

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