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The organisers of an essay competition decide that the 1st, 2nd ,3rd ,4th participants will get money and the money will be given in the ratio of 9:7:5:3 . The total participants are 15 and the amount the organisers have is ₹3000. Find the amount of money given to the 1st position, 2nd position, 3rd position, 4th position participants?​

Question

The organisers of an essay competition decide that the 1st, 2nd ,3rd ,4th participants will get money and the money will be given in the ratio of 9:7:5:3 . The total participants are 15 and the amount the organisers have is ₹3000. Find the amount of money given to the 1st position, 2nd position, 3rd position, 4th position participants?​

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Solution

To solve this problem, we first need to understand the ratio and how it applies to the total amount of money available.

Step 1: Add up the parts of the ratio. The ratio is 9:7:5:3, so we add those numbers together to find the total parts. 9 + 7 + 5 + 3 = 24 parts

Step 2: Determine the value of each part. The total amount of money is ₹3000, so we divide this by the total number of parts to find the value of each part. ₹3000 ÷ 24 parts = ₹125 per part

Step 3: Multiply the value of each part by the number of parts for each position. 1st position: 9 parts x ₹125/part = ₹1125 2nd position: 7 parts x ₹125/part = ₹875 3rd position: 5 parts x ₹125/part = ₹625 4th position: 3 parts x ₹125/part = ₹375

So, the 1st position participant will receive ₹1125, the 2nd position participant will receive ₹875, the 3rd position participant will receive ₹625, and the 4th position participant will receive ₹375.

This problem has been solved

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