Mr. Price deposited $170 in his bank. The number of $5 bills was 3 times the number of$10 bills, and the number of $1 bills was 30 more than the number of $5 bills. How manybills of each type did he deposit?
Question
Mr. Price deposited 5 bills was 3 times the number of1 bills was 30 more than the number of $5 bills. How manybills of each type did he deposit?
Solution
Let's denote the number of 5 bills as 3x (since it's three times the number of 1 bills as 3x + 30 (since it's 30 more than the number of $5 bills).
According to the problem, the total amount of money is $170. We can express this as an equation:
10x (total amount of 5 bills) + 1*(3x + 30) (total amount of $1 bills) = 170
Solving this equation will give us the number of each type of bill.
Let's simplify the equation:
10x + 15x + 3x + 30 = 170
Combine like terms:
28x + 30 = 170
Subtract 30 from both sides:
28x = 140
Divide both sides by 28:
x = 5
So, Mr. Price deposited 5 $10 bills.
The number of 10 bills, so he deposited 3*5 = 15 $5 bills.
The number of 5 bills, so he deposited 15 + 30 = 45 $1 bills.
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