An electric dipole placed in an electric field of intensity 2 × 105 N/C at an angle of30° experiences a torque equal to 4 Nm. The charge on the dipole of dipole length2 cm is

The torque (τ) experienced by an electric dipole in an electric field is given by the formula:

τ = pEsinθ

where: τ is the torque, p is the dipole moment, E is the electric field intensity, and θ is the angle between the dipole moment and the electric field.

We can rearrange this formula to solve for the dipole moment (p):

p = τ / (Esinθ)

Substituting the given values:

p = 4 Nm / (2 × 10^5 N/C * sin(30°))

p = 4 Nm / (1 × 10^5 N/C)

p = 4 × 10^-5 Cm

The dipole moment (p) is also equal to the product of the charge (q) and the separation distance (d):

p = qd

We can rearrange this formula to solve for the charge (q):

q = p / d

Substituting the given values:

q = 4 × 10^-5 Cm / 2 cm

q = 2 × 10^-5 C

So, the charge on the dipole is 2 × 10^-5 C.

The torque τ experienced by an electric dipole in an electric field is given by the formula:

τ = pEsinθ

where: τ is the torque, p is the dipole moment, E is the electric field intensity, and θ is the angle between the dipole moment and the electric field.

We can rearrange this formula to solve for the dipole moment p:

p = τ / (Esinθ)

Substituting the given values:

p = 4 Nm / (2 × 10^5 N/C * sin(30°))

p = 4 Nm / (1 × 10^5 N/C)

p = 4 × 10^-5 Cm

The dipole moment p is also equal to the product of the charge q on the dipole and the dipole length d:

p = qd

We can rearrange this formula to solve for the charge q:

q = p / d

Substituting the given values:

q = 4 × 10^-5 Cm / 2 cm

q = 2 × 10^-5 C

So, the charge on the dipole is 2 × 10^-5 C.