Balance the following equations by adding the stoichiometric ratios and ionic charges (include the + or - charge). Do not leave the boxes blank or it will mark you incorrect. If the stoichiometry is 1 please insert 1 in the box(es) below. You don't have to add a 1 for the charge.Sodium carbonate is dissolved in water Na2CO3(s) → Na (aq) + CO3 (aq)
Question
Balance the following equations by adding the stoichiometric ratios and ionic charges (include the + or - charge). Do not leave the boxes blank or it will mark you incorrect. If the stoichiometry is 1 please insert 1 in the box(es) below. You don't have to add a 1 for the charge.Sodium carbonate is dissolved in water Na2CO3(s) → Na (aq) + CO3 (aq)
Solution
The unbalanced chemical equation for the dissolution of sodium carbonate in water is:
Na2CO3(s) --> Na(aq) + CO3(aq)
To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
Step 1: Balance the sodium atoms. There are 2 sodium atoms in Na2CO3 on the left side of the equation and only 1 on the right side. To balance the sodium atoms, we put a coefficient of 2 in front of Na(aq):
Na2CO3(s) --> 2Na(aq) + CO3(aq)
The balanced chemical equation is:
Na2CO3(s) --> 2Na+(aq) + CO3^2-(aq)
This indicates that one molecule of sodium carbonate dissociates into two sodium ions and one carbonate ion when dissolved in water.
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