To find the energy of the photons, we can use the formula for the energy of a photon, which is E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength.

Given:
h = 6.63 × 10^-34 J.s
c = 3 × 10^8 m/s
λ = 600 nm = 600 × 10^-9 m (since 1 nm = 10^-9 m)

Substituting these values into the formula, we get:

E = (6.63 × 10^-34 J.s * 3 × 10^8 m/s) / (600 × 10^-9 m)
E = 3.315 × 10^-19 J

But the question asks for the energy in electron volts (eV), not joules. We know that 1 eV = 1.6 × 10^-19 J, so we can convert the energy to eV by dividing by this conversion factor:

E = 3.315 × 10^-19 J / 1.6 × 10^-19 J/eV
E = 2.07 eV

Rounding off to one decimal place, the energy of the photons of this color is 2.1 eV.

Question

To find the energy of the photons, we can use the formula for the energy of a photon, which is E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength.

Given:
h = 6.63 × 10^-34 J.s
c = 3 × 10^8 m/s
λ = 600 nm = 600 × 10^-9 m (since 1 nm = 10^-9 m)

Substituting these values into the formula, we get:

E = (6.63 × 10^-34 J.s * 3 × 10^8 m/s) / (600 × 10^-9 m)
E = 3.315 × 10^-19 J

But the question asks for the energy in electron volts (eV), not joules. We know that 1 eV = 1.6 × 10^-19 J, so we can convert the energy to eV by dividing by this conversion factor:

E = 3.315 × 10^-19 J / 1.6 × 10^-19 J/eV
E = 2.07 eV

Rounding off to one decimal place, the energy of the photons of this color is 2.1 eV.

Knowee AI · Accepted Answer

To find the energy of the photons, we can use the formula for the energy of a photon, which is E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength.

Given:
h = 6.63 × 10^-34 J.s
c = 3 × 10^8 m/s
λ = 600 nm = 600 × 10^-9 m (since 1 nm = 10^-9 m)

Substituting these values into the formula, we get:

E = (6.63 × 10^-34 J.s * 3 × 10^8 m/s) / (600 × 10^-9 m)
E = 3.315 × 10^-19 J

But the question asks for the energy in electron volts (eV), not joules. We know that 1 eV = 1.6 × 10^-19 J, so we can convert the energy to eV by dividing by this conversion factor:

E = 3.315 × 10^-19 J / 1.6 × 10^-19 J/eV
E = 2.07 eV

Rounding off to one decimal place, the energy of the photons of this color is 2.1 eV.

The wavelength of visible light for the green color is 600 𝑛𝑚. The energy ofphotons of this color is __________ 𝑒𝑉 (rounded off to one decimal place).(Planck’s constant = 6.63 × 10−34 𝐽𝑠, 1 𝑒𝑉 = 1.6 × 10−19 𝐽,speed of light = 3 × 108 𝑚𝑠−1

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