A particle moving along a line has a displacement according to the function x(t)=t2−2t+4,𝑥(𝑡)=𝑡2−2𝑡+4, where x is measured in meters and t is measured in seconds. Find the average velocity over the time period t=[0,2].
Question
A particle moving along a line has a displacement according to the function x(t)=t2−2t+4,𝑥(𝑡)=𝑡2−2𝑡+4, where x is measured in meters and t is measured in seconds. Find the average velocity over the time period t=[0,2].
Solution
The average velocity of a particle over a time interval [a, b] is given by the formula:
V_avg = (x(b) - x(a)) / (b - a)
Here, the displacement function x(t) is given as x(t) = t^2 - 2t + 4. We need to find the average velocity over the time period t = [0, 2]. So, a = 0 and b = 2.
First, find x(a) by substituting t = 0 into the displacement function:
x(0) = (0)^2 - 2*(0) + 4 = 4
Next, find x(b) by substituting t = 2 into the displacement function:
x(2) = (2)^2 - 2*(2) + 4 = 4 - 4 + 4 = 4
Now, substitute x(a), x(b), a and b into the formula for average velocity:
V_avg = (x(2) - x(0)) / (2 - 0) = (4 - 4) / 2 = 0 m/s
So, the average velocity of the particle over the time period t = [0, 2] is 0 m/s.
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