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Isabel is arranging 11 cans of food in a row on a shelf. She has 7 cans of carrots, 3 cans of beans, and 1 can of beets. In how many distinct orders can the cans be arranged if two cans of the same food are considered identical (not distinct)?

Question

Isabel is arranging 11 cans of food in a row on a shelf. She has 7 cans of carrots, 3 cans of beans, and 1 can of beets. In how many distinct orders can the cans be arranged if two cans of the same food are considered identical (not distinct)?

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Solution

This problem can be solved using the formula for permutations of a multiset, which is n! / (r1! * r2! * ... * rk!), where n is the total number of items and r1, r2, ..., rk are the numbers of each type of item.

Here, n = 11 (the total number of cans), r1 = 7 (the number of carrot cans), r2 = 3 (the number of bean cans), and r3 = 1 (the number of beet cans).

So, the number of distinct orders is 11! / (7! * 3! * 1!) = 39,916,800 / (5,040 * 6 * 1) = 1,320.

This problem has been solved

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