What will be the output of the following Python code?x = ('count',)m = 2for k in range(int(m)): x = (x,) print(x)Options(('count',)’count’,)((('count',)’count’,)’count’,)(('count',),)((('count',),),)Error, tuples are immutable((‘count’,)’count’,)
Question
What will be the output of the following Python code?x = ('count',)m = 2for k in range(int(m)): x = (x,) print(x)Options(('count',)’count’,)((('count',)’count’,)’count’,)(('count',),)((('count',),),)Error, tuples are immutable((‘count’,)’count’,)
Solution
The output of the given Python code will be:
(('count',),) ((('count',),),)
Here's the step-by-step explanation:
- The variable
xis initialized as a tuple with one element 'count'. - The variable
mis set to 2. - A for loop is set to run
mtimes, which is 2 times in this case. - In each iteration of the loop,
xis redefined as a tuple with one element, which is the previous value ofx. So, in the first iteration,xbecomes (('count',),) and in the second iteration,xbecomes ((('count',),),). - The value of
xis printed in each iteration. So, the output is (('count',),) in the first iteration and ((('count',),),) in the second iteration.
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