ProblemEarlier, you were told about a toy rocket fired into the air from the top of a barn. Its height (hℎ) above the ground in yards after x𝑥 seconds is given by the function:h(x)=−5x2+10x+20ℎ(𝑥)=−5𝑥2+10𝑥+20What was the maximum height of the rocket? SolutionThe maximum height was reached by the rocket at one second as you found in part b from the previous example. It takes second to reach the maximum height. We will substitute that value in for x𝑥 in our function and simplify.The maximum height reached by the rocket was yards. What is the time it takes for the rocket to hit the ground? (Use a graph or any other method to solve.)It takes approximately seconds for the rocket to hit the ground. (Round to the nearest tenth.)CheckQuestion 9

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot.y, equals, minus, 16, x, squared, plus, 162, x, plus, 82y=−16x 2 +162x+82AnswerAttempt 1 out of 2

A rocket is launched in the air. Its height in feet is given by h, of, t, equals, minus, 16, t, squared, plus, 8, th(t)=−16t 2 +8t where tt represents the time in seconds after launch. How many seconds have gone by when the rocket is at its highest point?

A rocket is fired vertically from theground. It moves upwards with aconstant acceleration of 10 𝑚/𝑠2. After30 seconds the fuel is finished. Afterwhat time from the instant of firing therocket will it attain the maximumheight? 𝑔 = 10 𝑚 /𝑠2:

A model rocket is launched from the deck in Jim’s backyard and the path followed by the rocket can bemodelled by the relation ℎ = −5% ! + 100% + 15, where ℎ, in meters, is the height that the model rocket reachesafter % seconds.a) What is the height of the deck?

ProblemSuppose Jeremiah is a diver for his summer swim team. The function h(x)=−4.9x2+8x+5ℎ(𝑥)=−4.9𝑥2+8𝑥+5 represents Jeremiah's height (hℎ) in meters above the water x𝑥 seconds after he leaves the diving board.What is the initial height of the diving board?At what time did Jeremiah reach his maximum height?What was Jeremiah’s maximum height?Sketch a graph of the function. (You can use your calculator for this or create a table of values.) SolutionThe initial height of the diving board is when the time is zero.h(0)=−4.9x2+8x+5ℎ(0)=−4.9𝑥2+8𝑥+5h(0)=−4.9(0)2+8(0)+5ℎ(0)=−4.9(0)2+8(0)+5h(0)=0+0+5ℎ(0)=0+0+5h(0)=5ℎ(0)=5The initial height of the diving board is 55 m.The time at which Jeremiah reaches his maximum height is the x𝑥-coordinate of the vertex.x=−b2a𝑥=−𝑏2𝑎x=𝑥=2(2( ))x=−8−9.8𝑥=−8−9.8x=0.82𝑥=0.82 secIt took Jeremiah seconds to reach his maximum height.The maximum height was reached Jeremiah at seconds. The maximum height is the y𝑦-coordinate of the vertex.h(t)=−4.9x2+8x+5ℎ(𝑡)=−4.9𝑥2+8𝑥+5h(0.82)=−4.9(0.82)2+8(0.82)+5ℎ(0.82)=−4.9(0.82)2+8(0.82)+5h(0.82)=−3.29+6.56+5ℎ(0.82)=−3.29+6.56+5h(0.82)=8.27ℎ(0.82)=8.27 mThe maximum height reached by Jeremiah was m.CheckQuestion 8