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Consider following three statements.  I. StringBuilder sb =new StringBuilder("OCAJP");II. StringBuilder sb0 =new StringBuilder("OCAJP ");III. String s =new String ("OCAJP");Which of the following will result true?*sb == sb0s.equals(sb)sb.equals(sb0)sb.toString().equals(s.toString())s == sb

Question

Consider following three statements.  I. StringBuilder sb =new StringBuilder("OCAJP");II. StringBuilder sb0 =new StringBuilder("OCAJP ");III. String s =new String ("OCAJP");Which of the following will result true?*sb == sb0s.equals(sb)sb.equals(sb0)sb.toString().equals(s.toString())s == sb

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Solution

The correct answer is sb.toString().equals(s.toString()).

Here's why:

  1. sb == sb0: This is false because sb and sb0 are two different objects in memory.

  2. s.equals(sb): This is false because s is a String and sb is a StringBuilder. The equals() method checks for equality of the values and the types. Since the types are different, this will return false.

  3. sb.equals(sb0): This is false because StringBuilder does not override the equals() method from the Object class. Therefore, it uses the Object's equals() method, which

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