When CH3NH2 is treated with HCl, one of the products is Cl−. Draw the other product.
Question
When CH3NH2 is treated with HCl, one of the products is Cl−. Draw the other product.
Solution
When CH3NH2 (methylamine) is treated with HCl (hydrochloric acid), it forms a salt. The reaction can be written as follows:
CH3NH2 + HCl -> CH3NH3+ + Cl-
So, the other product is CH3NH3+ (methylammonium ion).
To draw the structure of CH3NH3+:
- Start by drawing a Nitrogen (N) atom in the center.
- Draw three Hydrogen (H) atoms and one Methyl (CH3) group attached to the Nitrogen atom.
- Since it's a positive ion, add a plus sign to indicate the positive charge on the Nitrogen atom.
Remember that Nitrogen has a lone pair of electrons which is used to form a coordinate bond with the proton (H+) from HCl, resulting in the positive charge.
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