Given that A is a square matrix and A^2 = A, we can say that A(A-I) = 0, where I is the identity matrix.

This implies that the matrix A has eigenvalues 0 and 1.

The determinant of a matrix is the product of its eigenvalues. Therefore, the determinant of A, denoted as |A|, is 0*1 = 0.

So, |A| = 0.

Question

Given that A is a square matrix and A^2 = A, we can say that A(A-I) = 0, where I is the identity matrix.

This implies that the matrix A has eigenvalues 0 and 1.

The determinant of a matrix is the product of its eigenvalues. Therefore, the determinant of A, denoted as |A|, is 0*1 = 0.

So, |A| = 0.

Knowee AI · Accepted Answer

Given that A is a square matrix and A^2 = A, we can say that A(A-I) = 0, where I is the identity matrix.

This implies that the matrix A has eigenvalues 0 and 1.

The determinant of a matrix is the product of its eigenvalues. Therefore, the determinant of A, denoted as |A|, is 0*1 = 0.

So, |A| = 0.

If a square matrix A is such that A^2=A, then find |A|.