A cricket player catches a ball of mass 120 g moving with 25 m/s speed. If the catching process is completed in 0.1 s then the magnitude of force exerted by the ball on the hand of player will be (in SI unit):
Question
A cricket player catches a ball of mass 120 g moving with 25 m/s speed. If the catching process is completed in 0.1 s then the magnitude of force exerted by the ball on the hand of player will be (in SI unit):
Solution
To solve this problem, we need to use the formula for force, which is:
F = m * a
Where: F is the force, m is the mass, and a is the acceleration.
First, we need to convert the mass from grams to kilograms, because the SI unit for mass is kilograms.
120 g = 0.12 kg
Next, we need to calculate the acceleration. Acceleration is the change in velocity divided by the time it takes for the change to occur. In this case, the velocity changes from 25 m/s to 0 m/s in 0.1 seconds. So:
a = (v_f - v_i) / t a = (0 m/s - 25 m/s) / 0.1 s a = -250 m/s²
The negative sign indicates that the acceleration is in the opposite direction of the initial velocity, which makes sense because the ball is slowing down.
Finally, we can calculate the force:
F = m * a F = 0.12 kg * -250 m/s² F = -30 N
The negative sign indicates that the force is in the opposite direction of the initial velocity. In other words, the force exerted by the ball on the hand of the player is 30 N.
Similar Questions
A player catches a ball of mass 200g moving with speed of 5m/s by lowering his hands to a distance of .5m. The average force exerted by ball on his hands will be
Assume that a catcher in a MLB game exerts a force of - 65.0 N to stop a baseball. If the baseball has a mass of 0.145 kg, what is its acceleration as it is being caught?
A cricket player bowls a 100g cricket ball, releasing it from a height of exactly 1.1m. Ignoring the effect of air resistance, if the cricket player wants to release the ball such that its velocity is exactly parallel to the ground, at what velocity does she need to release it so that it will land 13.8m from the point of release?Note: The height the ball has been released may have changed.Give your answer to one decimal place in units of m/s. Do not include the units in your answer i.e. you would write 8.6 m/s as 8.6
A ball of mass 0.2 kg is thrown vertically upwards by applying a force by hand.If the hand moves 0.2 m while applying the force and the ball goes up to 2 m height further, find the magnitude of the force.
A golf club strikes a 0.045-kg golf ball in order to launch it from the tee. Forsimplicity, assume that the average net force applied to the ball acts parallel to theball’s motion, has a magnitude of 6800 N, and is in contact with the ball for adistance of 0.010 m. With what speed does the ball leave the club?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.