Give the oxidation state of the metal in:[CrCl2(NH3)4]+.
Question
Give the oxidation state of the metal in:[CrCl2(NH3)4]+.
Solution
To find the oxidation state of the metal in [CrCl2(NH3)4]+, we need to consider the charges of all the ions and molecules in the complex.
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Chlorine (Cl) has an oxidation state of -1. Since there are two chlorine atoms, the total charge contributed by chlorine is -2.
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Ammonia (NH3) is a neutral molecule, so it does not contribute to the overall charge of the complex.
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The complex ion has an overall charge of +1.
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The oxidation state of the metal (in this case, chromium or Cr) is therefore determined by balancing the charges so that the sum of the oxidation states equals the overall charge of the complex.
So, if we let x be the oxidation state of Cr, we have:
x + (-2) + 0 = +1
Solving for x gives:
x = +1 + 2 = +3
Therefore, the oxidation state of the metal (chromium) in [CrCl2(NH3)4]+ is +3.
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