The formula H2SO4 + 2 KOH --> K2SO4 + 2 H2O describes the reaction between sulfuric acid and potassium hydroxide. In the titration done, 20 mL of KOH with an unknown concentration is put into a flask with bromthymol blue indicator. The KOH solution was titrated with a 0.25 M H2SO4 solution. Three trials were performed and each trial yielded to an endpoint of yellow-colored solution, which is the desired endpoint. After three trials, the following readings were obtained: 15.5, 15.1, and 14.9 mL respectively.Calculate the equivalent moles of Potassium hydroxide used in the titration. (Answer must be rounded off to 4 decimal places)
Question
The formula H2SO4 + 2 KOH --> K2SO4 + 2 H2O describes the reaction between sulfuric acid and potassium hydroxide. In the titration done, 20 mL of KOH with an unknown concentration is put into a flask with bromthymol blue indicator. The KOH solution was titrated with a 0.25 M H2SO4 solution. Three trials were performed and each trial yielded to an endpoint of yellow-colored solution, which is the desired endpoint. After three trials, the following readings were obtained: 15.5, 15.1, and 14.9 mL respectively.Calculate the equivalent moles of Potassium hydroxide used in the titration. (Answer must be rounded off to 4 decimal places)
Solution
To calculate the equivalent moles of Potassium hydroxide (KOH) used in the titration, we first need to find the average volume of H2SO4 used in the three trials.
Step 1: Calculate the average volume of H2SO4 used The volumes used in the three trials were 15.5 mL, 15.1 mL, and 14.9 mL. The average volume is calculated as follows:
Average volume = (15.5 mL + 15.1 mL + 14.9 mL) / 3 = 15.17 mL
Step 2: Convert the average volume from mL to L 1 mL = 0.001 L, so 15.17 mL = 0.01517 L
Step 3: Calculate the moles of H2SO4 used The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. So, we can calculate the moles of H2SO4 used as follows:
Moles of H2SO4 = Molarity * Volume = 0.25 M * 0.01517 L = 0.0037925 moles
Step 4: Calculate the equivalent moles of KOH used From the balanced chemical equation, we know that the mole ratio of H2SO4 to KOH is 1:2. Therefore, the moles of KOH used is twice the moles of H2SO4 used:
Moles of KOH = 2 * Moles of H2SO4 = 2 * 0.0037925 moles = 0.007585 moles
So, the equivalent moles of Potassium hydroxide used in the titration is approximately 0.0076 (rounded off to 4 decimal places).
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