Knowee
Questions
Features
Study Tools

A rectangular plot, 37 m long and 25 m broad has two concrete roads 6 m wide running in the middle of the plot, one parallel to the length and other parallel to the breadth. What would be the total cost of gravelling the plot, excluding the area covered by the roads at the rate of Rs. 5.73 per sq. meter?

Question

A rectangular plot, 37 m long and 25 m broad has two concrete roads 6 m wide running in the middle of the plot, one parallel to the length and other parallel to the breadth. What would be the total cost of gravelling the plot, excluding the area covered by the roads at the rate of Rs. 5.73 per sq. meter?

🧐 Not the exact question you are looking for?Go ask a question

Solution

Sure, let's solve this step by step:

Step 1: Calculate the total area of the plot. The area of a rectangle is given by the formula length × breadth. So, the total area of the plot is 37m × 25m = 925 sq.m.

Step 2: Calculate the area covered by the roads. There are two roads, one parallel to the length and the other parallel to the breadth. The area of each road is given by width × length. So, the area of the road parallel to the length is 6m × 37m = 222 sq.m and the area of the road parallel to the breadth is 6m × 25m = 150 sq.m. The total area covered by the roads is 222 sq.m + 150 sq.m = 372 sq.m.

Step 3: Calculate the area to be graveled. The area to be graveled is the total area of the plot minus the area covered by the roads. So, the area to be graveled is 925 sq.m - 372 sq.m = 553 sq.m.

Step 4: Calculate the total cost of gravelling. The cost of gravelling is given per sq.m. So, the total cost of gravelling is the area to be graveled × the cost per sq.m. So, the total cost is 553 sq.m × Rs. 5.73 = Rs. 3168.89.

This problem has been solved

Similar Questions

A rectangular lawn 70 meters by 50 meters has two roads each 6 meters wide running in the middle of it one parallel to length and the other parallel to breadth. The cost of gravelling the roads at 80 paise per sq meter isOptions280547.2None of these300.5

Two cross roads each of width 5 m have been constructed in the middle of a garden crossing each other at right angles, running parallel to the sides of the garden 70 m long and45 m wide. Find the cost of constructing the roads at the rate of 80 per sq.m.

Mason is getting quotes from two different landscaping companies to put river rock along one side of his house at a depth of 0.5 foot. The surface area of the space he wishes to install rock in is rectangular and has a length that is eight times its width.The first company charges $3.50 per cubic foot of rock and $80 for delivery. The second company charges $2.50 per cubic foot of rock and $120 for delivery.Which system of equations can be used to determine the value of the width, x, at which the cost of the two companies, y, is the same?

A rectangular plot has a concrete path running inner side of the plot is used as a lawn, which has an area of 432 sq.m. If the width of the path is 4 m and the length of the plot is greater than its breadth by 2m, what is the area of the rectangular plot? 980 m^2 975 m^2 984 m^2 960 m^2

Mrs. Kaushik has a square plot with themeasurement as shown in the figure. She wants toconstruct a house in the middle of the plot. A garden is developedaround the house. Find the total cost of developing a garden aroundthe house at the rate of ` 55 per m2

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.