Learning Goal:To learn the definition and applications of angular momentum including its relationship to torque.By now, you should be familiar with the concept of momentum, defined as the product of an object's mass and its velocity:p⃗ =mv⃗ 𝑝→=𝑚𝑣→.You may have noticed that nearly every translational concept or equation seems to have an analogous rotational one. So, what might be the rotational analogue of momentum?Just as the rotational analogue of force F⃗ 𝐹→, called the torque τ⃗ 𝜏→, is defined by the formulaτ⃗ =r⃗ ×F⃗ 𝜏→=𝑟→×𝐹→,the rotational analogue of momentum p⃗ 𝑝→, called the angular momentum L⃗ 𝐿→, is given by the formulaL⃗ =r⃗ ×p⃗ 𝐿→=𝑟→×𝑝→,for a single particle. For an extended body you must add up the angular momenta of all of the pieces.There is another formula for angular momentum that makes the analogy to momentum particularly clear. For a rigid body rotating about an axis of symmetry, which will be true for all parts in this problem, the measure of inertia is given not by the mass m𝑚 but by the rotational inertia (i.e., the moment of inertia) I𝐼. Similarly, the rate of rotation is given by the body's angular speed, ω𝜔. The product Iω⃗ 𝐼𝜔→ gives the angular momentum L⃗ 𝐿→ of a rigid body rotating about an axis of symmetry. (Note that if the body is not rotating about an axis of symmetry, then the angular momentum and the angular velocity may not be parallel.)Figure1 of 1Part APart completeWhich of the following is the SI unit of angular momentum?N⋅m/sN⋅m/skg⋅m/skg⋅m/skg⋅m2/s2kg⋅m2/s2kg⋅m2/skg⋅m2/sSubmitPrevious Answers CorrectPart BPart completeAn object has rotational inertia I𝐼. The object, initially at rest, begins to rotate with a constant angular acceleration of magnitude α𝛼. What is the magnitude of the angular momentum L𝐿 of the object after time t𝑡?Express your answer in terms of I𝐼, α𝛼, and t𝑡.View Available Hint(s)for Part BL𝐿 =Iαt𝐼𝛼𝑡SubmitPrevious Answers CorrectPart CPart completeA rigid, uniform bar with mass m𝑚 and length b𝑏 rotates about the axis passing through the midpoint of the bar perpendicular to the bar. The linear speed of the end points of the bar is v𝑣. What is the magnitude of the angular momentum L𝐿 of the bar?Express your answer in terms of m𝑚, b𝑏, v𝑣, and appropriate constants.View Available Hint(s)for Part CL𝐿 =mbv6𝑚𝑏𝑣6SubmitPrevious AnswersAll attempts used; correct answer displayedThe correct answer involves the variable b𝑏, which was not part of your answer.You may recall that, according to Newton's 2nd law, the rate of change of momentum of an object equals the net force acting on the object:dp⃗ dt=F⃗ net𝑑𝑝→𝑑𝑡=𝐹→net.Similarly, the rate of change of angular momentum of an object equals the net torque acting on the object:dL⃗ dt=τ⃗ net𝑑𝐿→𝑑𝑡=𝜏→net.Therefore, if the net torque acting on an object (or a system of objects) is zero (i.e., the system is "closed"), then the rate of change of angular momentum is also zero. In other words, the net angular momentum of a closed system is constant (conserved).This statement is known as the law of conservation of angular momentum. Just like the laws of conservation of energy and momentum, the law of conservation of angular momentum plays a major role in mechanics.Part DThe uniform bar shown in (Figure 1) has a length of 0.80 m. The bar begins to rotate from rest in the horizontal plane about the axis passing through its left end. What will be the magnitude of the angular momentum L𝐿 of the bar 6.0 s after the motion has begun? The forces acting on the bar are shown in (Figure 1).Express your answer in kg⋅m2/skg⋅m2/s to two significant figures.View Available Hint(s)for Part DActivate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeL𝐿 =