Suppose that we have three networks: A, B and C with IP requirements 500, 4000 and 208, respectively. If You are given an IP block 130.3.0.0, allocate IPs performing subnetting.
Question
Suppose that we have three networks: A, B and C with IP requirements 500, 4000 and 208, respectively. If You are given an IP block 130.3.0.0, allocate IPs performing subnetting.
Solution
Sure, here is how you can allocate IPs performing subnetting for networks A, B and C:
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Identify the Class of IP Address: The given IP block 130.3.0.0 is a Class B address. The default subnet mask for Class B is 255.255.0.0.
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Determine the Network Requirements: The networks A, B and C require 500, 4000 and 208 IP addresses respectively.
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Calculate the Subnet Mask for Each Network:
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For Network A, the closest power of 2 to 500 is 512 (2^9). So, we need 9 bits for hosts. The subnet mask would be 255.255.254.0 (/23).
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For Network B, the closest power of 2 to 4000 is 4096 (2^12). So, we need 12 bits for hosts. The subnet mask would be 255.255.240.0 (/20).
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For Network C, the closest power of 2 to 208 is 256 (2^8). So, we need 8 bits for hosts. The subnet mask would be 255.255.255.0 (/24).
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Allocate IP Addresses to Each Network:
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For Network A, the IP range would be 130.3.0.0 to 130.3.1.255 with subnet mask 255.255.254.0.
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For Network B, the IP range would be 130.3.2.0 to 130.3.17.255 with subnet mask 255.255.240.0.
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For Network C, the IP range would be 130.3.18.0 to 130.3.18.255 with subnet mask 255.255.255.0.
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Please note that the first and last IP in each subnet is reserved for network address and broadcast address respectively. So, the usable IP addresses for each network would be from 130.3.0.1 to 130.3.1.254 for Network A, 130.3.2.1 to 130.3.17.254 for Network B, and 130.3.18.1 to 130.3.18.254 for Network C.
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