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Diana has 49 pencils, 21 pens and 84 erasers.She wants to pack the stationery equally into packets without any items left over.Write your answers in numerals.(a) The greatest number of packets she can pack is .(b) Each packet will contain  pencils,  pens and  erasers.

Question

Diana has 49 pencils, 21 pens and 84 erasers.She wants to pack the stationery equally into packets without any items left over.Write your answers in numerals.(a) The greatest number of packets she can pack is .(b) Each packet will contain  pencils,  pens and  erasers.

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Solution

To solve this problem, we need to find the greatest common divisor (GCD) of the numbers 49 (pencils), 21 (pens), and 84 (erasers). The GCD is the largest number that can divide all these numbers without leaving a remainder.

Step 1: Find the GCD of 49, 21, and 84.

The GCD of 49, 21, and 84 is 7.

(a) The greatest number of packets she can pack is 7.

Step 2: Find out how many pencils, pens, and erasers go into each packet.

Divide the number of each item by the GCD.

Pencils: 49 ÷ 7 = 7 Pens: 21 ÷ 7 = 3 Erasers: 84 ÷ 7 = 12

(b) Each packet will contain 7 pencils, 3 pens, and 12 erasers.

This problem has been solved

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