How much heat is absorbed when 2.5 moles of C(s) reacts in the presence of excess SO2(g) to produce CS2(l) and CO(g) according to the following chemical equation? 5 C(s) + 2 SO2(g) –> CS2(l) + 4 CO(g) ΔH° = +239.9 kJ Group of answer choices96.0 kJ600.0 kJ2399 kJ120.0 kJ
Question
How much heat is absorbed when 2.5 moles of C(s) reacts in the presence of excess SO2(g) to produce CS2(l) and CO(g) according to the following chemical equation? 5 C(s) + 2 SO2(g) –> CS2(l) + 4 CO(g) ΔH° = +239.9 kJ Group of answer choices96.0 kJ600.0 kJ2399 kJ120.0 kJ
Solution
The given balanced chemical equation is:
5 C(s) + 2 SO2(g) –> CS2(l) + 4 CO(g) with ΔH° = +239.9 kJ
This means that 239.9 kJ of heat is absorbed when 5 moles of C(s) react with excess SO2(g).
We are asked to find the heat absorbed when 2.5 moles of C(s) react.
Since the heat absorbed is directly proportional to the number of moles, we can set up the following proportion:
5 moles / 239.9 kJ = 2.5 moles / x kJ
Solving for x gives us:
x = (2.5 moles * 239.9 kJ) / 5 moles = 119.95 kJ
So, the heat absorbed when 2.5 moles of C(s) react is approximately 120.0 kJ.
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