cosecA−sinA)(secA−cosA)=1tanA+cotA
Question
cosecA−sinA)(secA−cosA)=1tanA+cotA
Solution
To solve the given equation, we will simplify both sides step by step.
Starting with the left side of the equation:
(cosecA - sinA)(secA - cosA)
First, let's expand the brackets:
cosecA * secA - cosecA * cosA - sinA * secA + sinA * cosA
Next, let's simplify each term:
1/cosA * 1/secA - 1/sinA * cosA - sinA * 1/secA + sinA * cosA
Simplifying further:
1/(cosA * secA) - cosA/sinA - sinA/secA + sinA * cosA
Now, let's simplify the right side of the equation:
1/tanA + cotA
Since cotA is the reciprocal of tanA, we can rewrite the right side as:
1/tanA + 1/tanA
Combining the terms:
2/tanA
Now, let's compare the simplified left side and right side of the equation:
1/(cosA * secA) - cosA/sinA - sinA/secA + sinA * cosA = 2/tanA
To further simplify, let's convert all trigonometric functions to sine and cosine:
1/(cosA * (1/cosA)) - (cosA/sinA) - (sinA/(1/cosA)) + sinA * cosA = 2/(sinA/cosA)
Simplifying:
1 - cosA/sinA - sinA/cosA + sinA * cosA = 2cosA/sinA
Now, let's multiply both sides by sinA to eliminate the denominators:
sinA - cosA - sinA^2 + sinA^2 * cosA = 2cosA
Simplifying further:
sinA - cosA = 2cosA
Now, let's move all terms to one side of the equation:
sinA - cosA - 2cosA = 0
Combining like terms:
sinA - 3cosA = 0
And that is the simplified form of the equation.
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