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Consider a general set, A, which is a subset of a general set, Ω. Suppose also that B is the complement of A, i.e. B=Ac=Ω∖A.Next let C be a subset of A (i.e. C⊆A) and D be a subset of B (i.e. D⊆B).Tick the most appropriate answer:B∖D=DA∖C=AA∪A=AAll of the above

Question

Consider a general set, A, which is a subset of a general set, Ω. Suppose also that B is the complement of A, i.e. B=Ac=Ω∖A.Next let C be a subset of A (i.e. C⊆A) and D be a subset of B (i.e. D⊆B).Tick the most appropriate answer:B∖D=DA∖C=AA∪A=AAll of the above

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Solution

The correct answer is A∪A=A.

Here's why:

  1. B\D=D: This is not correct. B\D represents all elements that are in B but not in D. Since D is a subset of B, B\D could be an empty set if D=B, but it will not be D.

  2. A\C=A: This is not correct. A\C represents all elements that are in A but not in C. Since C is a subset of A, A\C could be an empty set if C=A, but it will not be A.

  3. A∪A=A: This is correct. The union of a set with itself is always the set itself.

So, the most appropriate answer is A∪A=A.

This problem has been solved

Similar Questions

De Morgan's Law allows us to express the complement of the union of two sets in terms of:a.The union of the complements of the setsb.The intersection of the complements of the setsc.The complement of the intersection of the setsd.The complement of the symmetric difference of the sets

Define: Set, Subset, Complement

The following set notation will be used:• n(A) Number of elements in set A• ∈ “… is an element of …”• ∉ “… is not an element of …”• A′ Complement of set A• ∅ The empty set• Universal set• A ⊆ B A is a subset of B• A ⊈ B A is not a subset of B• A ∪ B Union of A and B• A ∩ B Intersection of A and B.Example definition of sets:A = {x: x is a natural number}B = {(x, y): y = mx + c}C = {x: a ⩽ x ⩽ b}D = {a, b, c, …

If A ⊂ B and B ⊂ C, what can we conclude?a.A = Cb.C ⊂ Ac.B = Cd.A ⊂ C

It refers to any two sets denoted by A and B such that every element of A is also an element of B then A is called subset of B, written A ⊆ B

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