The mean (average) of any set of consecutive numbers (even or odd) is always the middle number. This is because the numbers are evenly distributed around the mean.

Since we have nine consecutive odd numbers, the middle number is the fifth number, which is also the mean, 53.

Odd numbers are always 2 units apart (for example, 1, 3, 5, 7, etc.). So, to find the first number, we subtract 2 four times from the mean (53).

53 - 2*4 = 53 - 8 = 45

So, the smallest number in this set of nine consecutive odd numbers is 45.

Question

The mean (average) of any set of consecutive numbers (even or odd) is always the middle number. This is because the numbers are evenly distributed around the mean.

Since we have nine consecutive odd numbers, the middle number is the fifth number, which is also the mean, 53.

Odd numbers are always 2 units apart (for example, 1, 3, 5, 7, etc.). So, to find the first number, we subtract 2 four times from the mean (53).

53 - 2*4 = 53 - 8 = 45

So, the smallest number in this set of nine consecutive odd numbers is 45.

Knowee AI · Accepted Answer

The mean (average) of any set of consecutive numbers (even or odd) is always the middle number. This is because the numbers are evenly distributed around the mean.

Since we have nine consecutive odd numbers, the middle number is the fifth number, which is also the mean, 53.

Odd numbers are always 2 units apart (for example, 1, 3, 5, 7, etc.). So, to find the first number, we subtract 2 four times from the mean (53).

53 - 2*4 = 53 - 8 = 45

So, the smallest number in this set of nine consecutive odd numbers is 45.

The mean of nine consecutive uneven numbers is 53. What is the least number?

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