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A family on a trip budgets $800 for meals and hotel accommodations. Suppose the price of a meal is $40. In addition, suppose the family could afford a total of eight nights in a hotel if they don't buy any meals. How many meals could the family afford if they gave up two nights in the hotel?Group of answer choices8251

Question

A family on a trip budgets 800formealsandhotelaccommodations.Supposethepriceofamealis800 for meals and hotel accommodations. Suppose the price of a meal is 40. In addition, suppose the family could afford a total of eight nights in a hotel if they don't buy any meals. How many meals could the family afford if they gave up two nights in the hotel?Group of answer choices8251

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Solution

Step 1: Determine the cost of one night at the hotel.

The family has budgeted 800forthetripandtheycouldaffordeightnightsinahoteliftheydontbuyanymeals.Therefore,thecostofonenightatthehotelis800 for the trip and they could afford eight nights in a hotel if they don't buy any meals. Therefore, the cost of one night at the hotel is 800 / 8 = $100.

Step 2: Determine the new budget for meals.

If the family gives up two nights in the hotel, they would save 2 * 100=100 = 200. This amount can be added to their budget for meals.

Step 3: Determine the number of meals the family can afford with the new budget.

The price of one meal is 40.Therefore,withanadditional40. Therefore, with an additional 200, the family can afford 200/200 / 40 = 5 additional meals.

So, the family could afford 5 meals if they gave up two nights in the hotel.

This problem has been solved

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