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Give the velocity of the electron in the first Bohr orbit (n=1).Give your answer in meters per second

Question

Give the velocity of the electron in the first Bohr orbit (n=1).Give your answer in meters per second

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Solution

The velocity of an electron in the first Bohr orbit can be calculated using the formula:

v = e^2/(2ε₀hn)

where:

  • e is the elementary charge (1.602 x 10^-19 C)
  • ε₀ is the permittivity of free space (8.854 x 10^-12 C^2/N m^2)
  • h is Planck's constant (6.626 x 10^-34 J s)
  • n is the principal quantum number (for the first Bohr orbit, n=1)

Substituting these values into the formula gives:

v = (1.602 x 10^-19 C)^2 / (2 * 8.854 x 10^-12 C^2/N m^2 * 6.626 x 10^-34 J s * 1)

This simplifies to:

v = 2.18 x 10^6 m/s

So, the velocity of the electron in the first Bohr orbit is approximately 2.18 x 10^6 meters per second.

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