A ball falls vertically downwards towards a horizontal floor and then rebounds along its original path, as illustrated in Fig. 3.1.The ball reaches the floor with speed 3.8 m s –1 . The ball is then in contact with the floor for a time of 0.081s before leaving it with speed 1.7 m s –1 . The mass of the ball is 0.062 kg.MediumCalculate the loss of kinetic energy of the ball during the collision.MediumDetermine the magnitude of the change in momentum of the ball during the collision.MediumShow that the magnitude of the average resultant force acting on the ball during the collision is 4.2 N.MediumUse the information in (iii) to calculate the magnitude of:1. the average force of the floor on the ball during the collision2. the average force of the ball on the floor during the collision.

To calculate the loss of kinetic energy of the ball during the collision, we can use the formula:

Loss of kinetic energy = (1/2) * mass * (initial velocity^2 - final velocity^2)

Given that the mass of the ball is 0.062 kg, the initial velocity is 3.8 m/s, and the final velocity is 1.7 m/s, we can substitute these values into the formula:

Loss of kinetic energy = (1/2) * 0.062 kg * (3.8 m/s)^2 - (1.7 m/s)^2

Simplifying the equation, we get:

Loss of kinetic energy = (1/2) * 0.062 kg * (14.44 m^2/s^2 - 2.89 m^2/s^2)

Loss of kinetic energy = (1/2) * 0.062 kg * 11.55 m^2/s^2

Loss of kinetic energy = 0.357 J

Therefore, the loss of kinetic energy of the ball during the collision is 0.357 J.

To determine the magnitude of the change in momentum of the ball during the collision, we can use the formula:

Change in momentum = mass * (final velocity - initial velocity)

Substituting the given values, we have:

Change in momentum = 0.062 kg * (1.7 m/s - 3.8 m/s)

Change in momentum = 0.062 kg * (-2.1 m/s)

Change in momentum = -0.1314 kg·m/s

Therefore, the magnitude of the change in momentum of the ball during the collision is 0.1314 kg·m/s.

To show that the magnitude of the average resultant force acting on the ball during the collision is 4.2 N, we can use the formula:

Average resultant force = (change in momentum) / (time of contact)

Given that the change in momentum is -0.1314 kg·m/s and the time of contact is 0.081 s, we can substitute these values into the formula:

Average resultant force = -0.1314 kg·m/s / 0.081 s

Average resultant force = -1.62 N

Since the magnitude of the force cannot be negative, we take the absolute value:

Average resultant force = 1.62 N

Therefore, the magnitude of the average resultant force acting on the ball during the collision is 1.62 N.

To calculate the magnitude of the average force of the floor on the ball during the collision, we can use Newton's third law of motion, which states that the force exerted by the floor on the ball is equal in magnitude and opposite in direction to the force exerted by the ball on the floor.

Therefore, the magnitude of the average force of the floor on the ball during the collision is 1.62 N.

Similarly, the magnitude of the average force of the ball on the floor during the collision is also 1.62 N.