Use the first derivative test to find the two critical points of the function. First point:(Either of the points can be 𝑥1 or 𝑥2.)𝑥1= Relative Maximum Relative Minimum Neither

Use the first derivative test to find the two critical points of the function. First point:

The function 𝑓(𝑥,𝑦)=𝑥3−3𝑥−2𝑥𝑦−𝑦2−2𝑦+4 has two critical points. Find and classify them. the left-most stationary point (the one with the lower value of x) is located at x = and y = and is a point. • the right-most stationary point (the one with the higher value of x) is located at x = and y = and is a point

Find the first derivative.𝑦′= Your last answer was interpreted as follows:−𝑥2−𝑥+30The variables found in your answer were: [𝑥]Use the first derivative test to find the two critical points of the function. First point:

Consider the following function.f(x) = x2 + 3.5x − 6(a) Write the derivative formula.f '(x) = 2x+3.5 (b) Locate any relative extreme points. (If an answer does not exist, enter DNE.)relative maximum      (x, y) = relative minimum (x, y) =

Find all relative extrema of the function. Use the second derivative test where applicable. (If an answer does not exist, enter DNE.)f(x) = x4 − 8x3 + 1