When a water solution of potassium hydroxide is added to a water solution of iron(III) nitrate, a precipitate of iron(III) hydroxide forms.  What is the correctly balanced net ionic equation for the reaction?Group of answer choices3OH–(aq) + Fe3+(aq)  →   Fe(OH)3(s)K+(aq) + 3OH–(aq) + NO3–(aq) + Fe3+(aq)  →  K+(aq) + NO3–(aq) + Fe(OH)3(s)KOH(aq) + Fe(NO3)3(aq)  →  KNO3(aq) + Fe(OH)3(s)3K+(aq) + 3OH–(aq) + 3NO3–(aq) + Fe3+(aq)  →  3K+(aq) + 3NO3–(aq) + Fe(OH)3(s)3KOH(aq) + Fe(NO3)3(aq)  →  3KNO3(aq) + Fe(OH)3(s)

When a water solution of copper(II) sulfate is added to a water solution of sodium phosphate, a precipitate of copper(II) phosphate forms.  What is the correctly balanced net ionic equation for the reaction?Group of answer choicesCuSO4(aq) + Na3PO4(aq) → Cu3(PO4)2(s) + Na2SO4(aq)3Cu2+(aq) + 2PO43–(aq) → Cu3(PO4)2(s)3Cu2+(aq) + 6Na+(aq) + 2PO43–(aq) + 3SO42–(aq) → Cu3(PO4)2(s) + 3SO42–(aq) + 6Na+(aq)3CuSO4(aq) + 2Na3PO4(aq) → Cu3(PO4)2(s) + 3Na2SO4(aq)Cu2+(aq) + PO42–(aq) → CuPO4(s)

Write the complete ionic equation and the net ionic equation for the reaction below. The reaction does not need to be balanced. 1 point, for each compound, predicted and written correctly.1 point, one for each ion found in the complete ionic equation that is written correctly1 point for the correctly written net ionic equationPb(NO3)2(aq) + KI(aq) --->

When excess dilute sulfuric acid is added to a water solution of potassium carbonate, a colourless gas is evolved.  What is the correctly balanced net ionic equation for the reaction

2 Balance the equations ---i.KMnO4 +HCl → KCl + MnCl2 + H2O+Cl2.ii. FeCl3 + NaOH → Fe(OH)3 +NaCliii. NH3 +O2→ NO +H₂Oiv. P2O5 +H2O → H3PO4v. H2S + SO2 → S + H₂O​

What is the balanced, net ionic equation for the reaction represented by this equation?HCl + NaOH  NaCl + HOQuestion 18Select one:a.Na+(aq)(𝑎𝑞)+ + Cl−(aq)(𝑎𝑞)−→→ Na+(aq)(𝑎𝑞)+ + Cl−(aq)(𝑎𝑞)−b.H+(aq)(𝑎𝑞)+ + Cl−(aq)(𝑎𝑞)− + Na+(aq)(𝑎𝑞)+ + OH−(aq)(𝑎𝑞)−→→ Na+(aq)(𝑎𝑞)+ + Cl−(aq)(𝑎𝑞)− + H+(aq)(𝑎𝑞)+ + OH−(aq)(𝑎𝑞)−c.H+(aq)(𝑎𝑞)+ + Cl−(aq)(𝑎𝑞)− + Na+(aq)(𝑎𝑞)+ + OH−(aq)(𝑎𝑞)−→→ Na+(aq)(𝑎𝑞)+ + Cl−(aq)(𝑎𝑞)− + H22Ol𝑙d.H+(aq)(𝑎𝑞)+ + OH−(aq)(𝑎𝑞)−→→ H22Ol