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In Arizona, photovoltaic (PV) panels can generate an average annual power of 1 MW/acre. If there are 311 sunny days per year in Arizona, but only 160 sunny days per year in Pennsylvania, how much average power (in MW/acre) could the same PV panels generate in Pennsylvania? Please include two decimal places in your answer. Note: assume that a cloudy day delivers 0 watts/acre of solar power. This is not true, but it simplifies the problem for us.You Answered

Question

In Arizona, photovoltaic (PV) panels can generate an average annual power of 1 MW/acre. If there are 311 sunny days per year in Arizona, but only 160 sunny days per year in Pennsylvania, how much average power (in MW/acre) could the same PV panels generate in Pennsylvania? Please include two decimal places in your answer. Note: assume that a cloudy day delivers 0 watts/acre of solar power. This is not true, but it simplifies the problem for us.You Answered

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Solution

To solve this problem, we need to find the ratio of sunny days in Pennsylvania to sunny days in Arizona and then multiply this ratio by the power generated in Arizona.

Step 1: Find the ratio of sunny days in Pennsylvania to sunny days in Arizona.

The ratio is 160 (sunny days in Pennsylvania) divided by 311 (sunny days in Arizona).

160/311 = 0.5145 (rounded to four decimal places)

Step 2: Multiply this ratio by the power generated in Arizona.

The power generated in Arizona is 1 MW/acre. So, we multiply this by the ratio we found in step 1.

1 MW/acre * 0.5145 = 0.5145 MW/acre

So, the same PV panels could generate an average power of 0.51 MW/acre in Pennsylvania (rounded to two decimal places).

This problem has been solved

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