Which of the following functions grows the fastest?A.๐(๐ก)=2๐กโ๐ก3f(t)=2 t โt 3 B.๐(๐ก)=(1.1)๐กd(t)=(1.1) t C.๐(๐ก)=๐ก4โ3๐ก+9b(t)=t 4 โ3t+9D.โ(๐ก)=5๐ก+๐ก5h(t)=5 t +t 5 E.๐(๐ก)=๐ก2โ5๐กc(t)= t 2 โ5tโ
Question
Which of the following functions grows the fastest?A.๐(๐ก)=2๐กโ๐ก3f(t)=2 t โt 3 B.๐(๐ก)=(1.1)๐กd(t)=(1.1) t C.๐(๐ก)=๐ก4โ3๐ก+9b(t)=t 4 โ3t+9D.โ(๐ก)=5๐ก+๐ก5h(t)=5 t +t 5 E.๐(๐ก)=๐ก2โ5๐กc(t)= t 2 โ5tโ
Solution
To determine which function grows the fastest, we need to look at the highest degree of the polynomial in each function. The degree of a polynomial is the highest power of the variable (in this case, t).
A. ๐(๐ก)=2๐กโ๐ก^3: The highest degree is 3. B. ๐(๐ก)=(1.1)๐ก: This is an exponential function, which grows faster than any polynomial function. C. ๐(๐ก)=๐ก^4โ3๐ก+9: The highest degree is 4. D. โ(๐ก)=5๐ก+๐ก^5: The highest degree is 5. E. ๐(๐ก)=๐ก^2โ5๐ก: The highest degree is 2.
So, the function that grows the fastest is B. ๐(๐ก)=(1.1)๐ก, the exponential function.
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A.๐(๐ก)=2๐กโ๐ก3f(t)=2 t โt 3 B.๐(๐ก)=(1.1)๐กd(t)=(1.1) t C.๐(๐ก)=๐ก4โ3๐ก+9b(t)=t 4 โ3t+9D.โ(๐ก)=5๐ก+๐ก5h(t)=5 t +t 5 E.๐(๐ก)=๐ก2โ5๐กc(t)= t 2 โ5tโ
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