force ‘F’ is applied at the top of a ring of mass ‘M’ and radius ‘R’ placed on a rough horizontal surface as shown in the figure. Friction is sufficient to prevent slipping. The friction force acting on the ring is
Question
force ‘F’ is applied at the top of a ring of mass ‘M’ and radius ‘R’ placed on a rough horizontal surface as shown in the figure. Friction is sufficient to prevent slipping. The friction force acting on the ring is
Solution
The friction force acting on the ring can be calculated using the following steps:
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Identify the forces acting on the ring. In this case, we have the applied force 'F', the gravitational force 'Mg', and the frictional force 'f'.
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Since the ring is not slipping, the frictional force 'f' is equal to the applied force 'F'. This is due to Newton's third law, which states that for every action, there is an equal and opposite reaction.
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Therefore, the frictional force 'f' acting on the ring is equal to the applied force 'F'.
Please note that this is a simplified explanation and assumes that the force 'F' is applied horizontally and that there are no other forces acting on the ring.
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