Here is some data of a few patient's pulse measurement: 1) Find the mean of a variable "pulse rate". Find the standard deviation of a variable "pulse rate" Use the correct symbol and choose the correct formula from the list. Plug in numbers, you don't have actually to calculate it. The correct answer is 14.2227 bpm. What would be unusually high and unusually low pulse rate?

The table below contains pulse rates after running for 1 minute, collected from a sample of females who drink alcohol. The mean pulse rate after running for 1 minute of females who do not drink is 97 beats per minute. Do the data show that the mean pulse rate of females who do drink alcohol is higher than the mean pulse rate of females who do not drink? Test at the 8% level.pulse rate after running one minute in bpm78130731189393771351489288106458093951621144780841139744916977921211548481991149993P: Parameter     What is the correct parameter symbol for this problem?          What is the wording of the parameter in the context of this problem?     H: Hypotheses     Fill in the correct null and alternative hypotheses:𝐻0: bpm 𝐻𝐴: bpm A:  Assumptions     Since information was collected from each object, what conditions do we need to check?     Check all that apply.    σσ is knownoutliers in the data𝑛(𝑝̂)≥10𝑁≥20𝑛𝑛𝑝≥10no outliers in the data𝑛≥30 or normal population𝑛(1-𝑝)≥10σσ is unknown𝑛(1-𝑝̂)≥10     Check those assumptions:     1. Is the value of 𝜎 known?      2. Which of the following is the correct modified boxplot?         406080100120140160180pulse rate after running one minute in bpm448093137.75162[Graphs generated by this script: setBorder(15); initPicture(40,180,-3,6);axes(20,100,1,null,null,1,'off');text([99,-3],"pulse rate after running one minute in bpm");line([44,2],[44,4]); rect([80,2],[137.75,4]); line([93,2],[93,4]);line([162,2],[162,4]); line([44,3],[80,3]); line([137.75,3],[162,3]);fontsize*=.8;fontfill='blue';text([44,4],'44','above');text([80,4],'80','above');text([93,4],'93','above');text([137.75,4],'137.75','above');text([162,4],'162','above');fontfill='black';fontsize*=1.25;]406080100120140160180pulse rate after running one minute in bpm448086.5113.5162[Graphs generated by this script: setBorder(15); initPicture(40,180,-3,6);axes(20,100,1,null,null,1,'off');text([99,-3],"pulse rate after running one minute in bpm");line([44,2],[44,4]); rect([80,2],[113.5,4]); line([86.5,2],[86.5,4]);line([162,2],[162,4]); line([44,3],[80,3]); line([113.5,3],[162,3]);fontsize*=.8;fontfill='blue';text([44,4],'44','above');text([80,4],'80','above');text([86.5,4],'86.5','above');text([113.5,4],'113.5','above');text([162,4],'162','above');fontfill='black';fontsize*=1.25;]406080100120140160180pulse rate after running one minute in bpm448093113.5162[Graphs generated by this script: setBorder(15); initPicture(40,180,-3,6);axes(20,100,1,null,null,1,'off');text([99,-3],"pulse rate after running one minute in bpm");line([44,2],[44,4]); rect([80,2],[113.5,4]); line([93,2],[93,4]);line([162,2],[162,4]); line([44,3],[80,3]); line([113.5,3],[162,3]);fontsize*=.8;fontfill='blue';text([44,4],'44','above');text([80,4],'80','above');text([93,4],'93','above');text([113.5,4],'113.5','above');text([162,4],'162','above');fontfill='black';fontsize*=1.25;]406080100120140160180pulse rate after running one minute in bpm446293113.5162[Graphs generated by this script: setBorder(15); initPicture(40,180,-3,6);axes(20,100,1,null,null,1,'off');text([99,-3],"pulse rate after running one minute in bpm");line([44,2],[44,4]); rect([62,2],[113.5,4]); line([93,2],[93,4]);line([162,2],[162,4]); line([44,3],[62,3]); line([113.5,3],[162,3]);fontsize*=.8;fontfill='blue';text([44,4],'44','above');text([62,4],'62','above');text([93,4],'93','above');text([113.5,4],'113.5','above');text([162,4],'162','above');fontfill='black';fontsize*=1.25;]          Are there any outliers?      3. 𝑛 = which is           Is it reasonable to assume the population is normally distributed?  N: Name the test     The conditions are met to use a .T: Test Statistic     The symbol and value of the random variable on this problem are as follows:     = bpm     The test statistic formula set up with numbers is as follows:     Round values to 2 decimal places. 𝑡=𝑋¯-𝜇𝑠𝑛=(( - ) / / ))      The final answer for the test statistic from technology is as follows:     Round to 2 decimal places.     t = O: Obtain the P-value     Report the final answer to 4 decimal places.     It is possible when rounded that a p-value is 0.0000     P-value = M: Make a decision     Since the p-value , we .S: State a conclustion     There significant evidence to conclude bpm

An infant's pulse rate is measured to be 130±5130±5 beats/min. What is the percent uncertainty in this measurement?

A person measures his or her heart rate by counting the number of beats in 30s30s . If 40±140±1 beats are counted in 30.0±0.5s30.0±0.5s , what is the heart rate and its uncertainty in beats per minute?

(a) Suppose that a person has an average heart rate of 72.0 beats/min. How many beats does he or she have in 2.0 y? (b) In 2.00 y? (c) In 2.000 y?

The patient's heart rate registered at just _____ above average upon his admission to the hospital.試題24回答A.convenientlyB.slightlyC.exactlyD.annually