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Suppose you are given the relation {(1 , 2), (3 , 4), (5 , 6)}. What is an ordered pair that you could add to thisrelation to make it not a function? Why would this ordered pair make the relation not a function?

Question

Suppose you are given the relation {(1 , 2), (3 , 4), (5 , 6)}. What is an ordered pair that you could add to thisrelation to make it not a function? Why would this ordered pair make the relation not a function?

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Solution

An ordered pair that could be added to this relation to make it not a function is (1, 7). This is because in a function, each input (or 'x' value) can only be paired with one output (or 'y' value). In the given relation, the number 1 is already paired with the number 2. If we add the pair (1, 7), then the number 1 would be paired with both 2 and 7, which violates the definition of a function. Therefore, adding the pair (1, 7) would make the relation not a function.

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Similar Questions

Which set of ordered pairs does not represent a function? A (4, 1), (6, 2), (7, 5), (9, 2) B (0, 5), (1, 7), (2, 9), (3, 11) C (−2, 5), (0, 2), (9, −6), (8, 7) D (5, 5), (6, 10), (10, 15), (5, 20)

If any two ordered pairs have the same ____-coordinates but different ____-coordinates, therelation is not a function.Examples:1. {(3 , 1), (2 , 3), (1 , 5)}This relation _______is _______is not a function.→ Every value of x corresponds to: _______only one _______ more than one value of y.2. {(−1 , 4), (−2 , 5), (−2 , 3)}Here x = ____ is associated with two y values, ____ and ____.This relation _______is _______is not a function.

Which of the relations is not a function?

Given the sets of ordered pairs, determine if they represent a relation or a function. If it is a function,specify the domain and range. (Criteria A)a) {(1,2),(2,3),(1,5),(4,6)}{(1,2),(2,3),(1,5),(4,6)}b) {(3,4),(2,7),(5,2),(3,1)}{(3,4),(2,7),(5,2),(3,1)}c) {(2,3),(5,6),(2,7),(8,1)}{(2,3),(5,6),(2,7),(8,1)}d) {(1,3),(2,5),(3,7),(4,9)}{(1,3),(2,5),(3,7),(4,9)}

Which of the following relations is not a function?*R = {(1,2), (1,4), (3,1), (5,1)}R = {(1,2), (3,4), (2,1), (5,2)}R = {(2,1), (4,4), (3,1), (5,1)}R = {(1,2), (3,4), (2,1), (5,1)}

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