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Point out the error line in the following program.1. #include<stdio.h>2. #include<string.h>3.  int main()4.  {5.      static char str1[] = "Welcome";6.      static char str2[20];7.      static char str3[] = "Sir";8.      str2 = strcpy(str3, str1);9.      printf("%s\n", str2);10.      return 0;11. }Select one:Line number 8Line number 6None of these.Line number 7

Question

Point out the error line in the following program.1. #include<stdio.h>2. #include<string.h>3.  int main()4.  {5.      static char str1[] = "Welcome";6.      static char str2[20];7.      static char str3[] = "Sir";8.      str2 = strcpy(str3, str1);9.      printf("%s\n", str2);10.      return 0;11. }Select one:Line number 8Line number 6None of these.Line number 7

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Solution

The error is in line number 8. In C, you cannot assign arrays directly. The strcpy function already copies the source string into the destination string, so the assignment is not needed. The corrected line should be:

strcpy(str2, str1);

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