Let's break down the problem step by step:

1. Let's assume the total distance from A to B is 2D (for simplicity of calculation). So, the distance from A to B or B to A is D.

2. Onward journey (A to B): Half of the distance D/2 is covered by bike and the other half D/2 is covered by car.

Time taken by bike = Distance/Speed = (D/2) / 50 = D/100 hours
Time taken by car = Distance/Speed = (D/2) / 70 = D/140 hours
Total time for onward journey = D/100 + D/140 = 12D/700 = 6D/350 hours

3. Return journey (B to A): Half of the time is spent on bike and the other half on car.

Let's assume the total time taken for return journey is T hours. So, T/2 hours is spent on bike and T/2 hours on car.
Distance covered by bike = Speed * Time = 50 * (T/2) = 25T
Distance covered by car = Speed * Time = 70 * (T/2) = 35T
But the total distance from B to A is D. So, 25T + 35T = D = 60T = D = T = D/60
Total time for return journey = D/60 hours

4. The ratio of the onward travel time to return travel time is (6D/350) : (D/60) = 36 : 35

So, the correct answer is 36 : 35.

Question

Let's break down the problem step by step:

1. Let's assume the total distance from A to B is 2D (for simplicity of calculation). So, the distance from A to B or B to A is D.

2. Onward journey (A to B): Half of the distance D/2 is covered by bike and the other half D/2 is covered by car.

Time taken by bike = Distance/Speed = (D/2) / 50 = D/100 hours
   Time taken by car = Distance/Speed = (D/2) / 70 = D/140 hours
   Total time for onward journey = D/100 + D/140 = 12D/700 = 6D/350 hours

3. Return journey (B to A): Half of the time is spent on bike and the other half on car.

Let's assume the total time taken for return journey is T hours. So, T/2 hours is spent on bike and T/2 hours on car.
   Distance covered by bike = Speed * Time = 50 * (T/2) = 25T
   Distance covered by car = Speed * Time = 70 * (T/2) = 35T
   But the total distance from B to A is D. So, 25T + 35T = D => 60T = D => T = D/60
   Total time for return journey = D/60 hours

4. The ratio of the onward travel time to return travel time is (6D/350) : (D/60) = 36 : 35

So, the correct answer is 36 : 35.

Knowee AI · Accepted Answer

Let's break down the problem step by step:

1. Let's assume the total distance from A to B is 2D (for simplicity of calculation). So, the distance from A to B or B to A is D.

2. Onward journey (A to B): Half of the distance D/2 is covered by bike and the other half D/2 is covered by car.

Time taken by bike = Distance/Speed = (D/2) / 50 = D/100 hours
   Time taken by car = Distance/Speed = (D/2) / 70 = D/140 hours
   Total time for onward journey = D/100 + D/140 = 12D/700 = 6D/350 hours

3. Return journey (B to A): Half of the time is spent on bike and the other half on car.

Let's assume the total time taken for return journey is T hours. So, T/2 hours is spent on bike and T/2 hours on car.
   Distance covered by bike = Speed * Time = 50 * (T/2) = 25T
   Distance covered by car = Speed * Time = 70 * (T/2) = 35T
   But the total distance from B to A is D. So, 25T + 35T = D => 60T = D => T = D/60
   Total time for return journey = D/60 hours

4. The ratio of the onward travel time to return travel time is (6D/350) : (D/60) = 36 : 35

So, the correct answer is 36 : 35.

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