what is melting point of benzene on kelvin scale , if∆fusion=9Kj/mol and ∆Sfusion =30J/k—mol ?
Question
what is melting point of benzene on kelvin scale , if∆fusion=9Kj/mol and ∆Sfusion =30J/k—mol ?
Solution
To find the melting point of benzene on the Kelvin scale, we can use the equation:
∆G = ∆H - T∆S
where ∆G is the change in Gibbs free energy, ∆H is the enthalpy change, T is the temperature in Kelvin, and ∆S is the entropy change.
Given that ∆fusion = 9 kJ/mol and ∆Sfusion = 30 J/K-mol, we need to convert the units to match the equation.
∆fusion = 9 kJ/mol = 9000 J/mol ∆Sfusion = 30 J/K-mol
Now, we can rearrange the equation to solve for the melting point temperature (T):
T = (∆H - ∆G) / ∆S
Since ∆G = 0 at the melting point, the equation simplifies to:
T = ∆H / ∆S
Substituting the values:
T = 9000 J/mol / 30 J/K-mol
T = 300 K
Therefore, the melting point of benzene on the Kelvin scale is 300 K.
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