To solve this problem, we need to use the Doppler effect formula for sound. The Doppler effect describes the change in frequency of a wave in relation to an observer who is moving relative to the wave source.

The formula for the observed frequency $ f' $ when the source is stationary and the observer is moving towards the source is given by:

$$ f' = f \left( \frac{v + v_o}{v} \right) $$

where:
- $ f' $ is the observed frequency,
- $ f $ is the emitted frequency (2400 Hz),
- $ v $ is the speed of sound in air (350 m/s),
- $ v_o $ is the speed of the observer (14 m/s).

Now, let's plug in the values:

$$ f' = 2400 \left( \frac{350 + 14}{350} \right) $$

First, calculate the numerator:

$$ 350 + 14 = 364 $$

Next, divide by the speed of sound:

$$ \frac{364}{350} \approx 1.04 $$

Now, multiply by the emitted frequency:

$$ f' = 2400 \times 1.04 $$

$$ f' \approx 2496 \, \text{Hz} $$

So, the frequency sound that Samira hears is approximately 2496 Hz.

Question

To solve this problem, we need to use the Doppler effect formula for sound. The Doppler effect describes the change in frequency of a wave in relation to an observer who is moving relative to the wave source.

The formula for the observed frequency $ f' $ when the source is stationary and the observer is moving towards the source is given by:

$$ f' = f \left( \frac{v + v_o}{v} \right) $$

where:
- $ f' $ is the observed frequency,
- $ f $ is the emitted frequency (2400 Hz),
- $ v $ is the speed of sound in air (350 m/s),
- $ v_o $ is the speed of the observer (14 m/s).

Now, let's plug in the values:

$$ f' = 2400 \left( \frac{350 + 14}{350} \right) $$

First, calculate the numerator:

$$ 350 + 14 = 364 $$

Next, divide by the speed of sound:

$$ \frac{364}{350} \approx 1.04 $$

Now, multiply by the emitted frequency:

$$ f' = 2400 \times 1.04 $$

$$ f' \approx 2496 \, \text{Hz} $$

So, the frequency sound that Samira hears is approximately 2496 Hz.

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