If R is the radius of the earth and g is the acceleration due to gravity on the earth’s surface, then the density of the earth isa.3g/4πGRb.4g/3πGRc.3G/4gπRd.3gR/4πG
Question
If R is the radius of the earth and g is the acceleration due to gravity on the earth’s surface, then the density of the earth isa.3g/4πGRb.4g/3πGRc.3G/4gπRd.3gR/4πG
Solution
To find the density of the earth, we can use the formula:
Density = Mass / Volume
First, let's find the mass of the earth. The mass of an object can be calculated using the formula:
Mass = Acceleration due to gravity * Radius^2 / Gravitational constant
Given that the acceleration due to gravity on the earth's surface is represented by "g" and the radius of the earth is represented by "R", we can substitute these values into the formula:
Mass = g * R^2 / G
Next, let's find the volume of the earth. The volume of a sphere can be calculated using the formula:
Volume = (4/3) * π * Radius^3
Substituting the value of the radius of the earth, we get:
Volume = (4/3) * π * R^3
Now, we can substitute the values of mass and volume into the density formula:
Density = Mass / Volume
Density = (g * R^2 / G) / ((4/3) * π * R^3)
Simplifying the expression, we get:
Density = (3g / 4πGR)
Therefore, the correct answer is option a) 3g/4πGR.
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