The given equation is a quadratic equation of the form ax^2 + bx + c = 0.

The product of the roots of a quadratic equation is given by c/a.

In this case, a = 81, b = 81m + n, and c = mn.

So, the product of the roots is mn/81.

Given that the product of the solutions to this equation is lmn, we can equate mn/81 = lmn.

Solving for l, we get l = 1/81.

Question

The given equation is a quadratic equation of the form ax^2 + bx + c = 0.

The product of the roots of a quadratic equation is given by c/a.

In this case, a = 81, b = 81m + n, and c = mn.

So, the product of the roots is mn/81.

Given that the product of the solutions to this equation is lmn, we can equate mn/81 = lmn.

Solving for l, we get l = 1/81.

Knowee AI · Accepted Answer

The given equation is a quadratic equation of the form ax^2 + bx + c = 0.

The product of the roots of a quadratic equation is given by c/a.

In this case, a = 81, b = 81m + n, and c = mn.

So, the product of the roots is mn/81.

Given that the product of the solutions to this equation is lmn, we can equate mn/81 = lmn.

Solving for l, we get l = 1/81.

81x2+(81m+n)x+mn=081𝑥2+(81𝑚+𝑛)𝑥+𝑚𝑛=0 In the given equation, m𝑚 and n𝑛 are positive constants. If the product of the solutions to this equation is lmn𝑙𝑚𝑛, where l𝑙 is a constant, what is the value of l𝑙?