The sum of five consecutive even numbers is equal to 260. what is the sum of the largest number amongst them and the half the square of the smallest numbers amongst them?Options13461288120816441274

The problem states that the sum of five consecutive even numbers is 260.

Step 1: Find the average of the numbers. Since they are consecutive even numbers, the average will be the middle number. So, 260/5 = 52.

Step 2: Identify the smallest and largest numbers. Since 52 is the middle number, the smallest number will be 52 - 22 = 48 and the largest number will be 52 + 22 = 56.

Step 3: Calculate half the square of the smallest number. (48^2)/2 = 1152.

Step 4: Add the largest number to half the square of the smallest number. 1152 + 56 = 1208.

So, the sum of the largest number amongst them and half the square of the smallest numbers amongst them is 1208.

The problem states that the sum of five consecutive even numbers is 260.

Step 1: Find the average of the numbers. Since they are consecutive even numbers, the average will be the middle number. So, 260/5 = 52.

Step 2: Identify the smallest and largest numbers. Since 52 is the third number, the sequence is 48, 50, 52, 54, 56. So, the smallest number is 48 and the largest is 56.

Step 3: Calculate half the square of the smallest number. (48^2)/2 = 1152.

Step 4: Add the largest number to the result from step 3. 1152 + 56 = 1208.

So, the sum of the largest number amongst them and half the square of the smallest number amongst them is 1208.

The problem states that the sum of five consecutive even numbers is 260.

Step 1: Find the average of the numbers. Since they are consecutive even numbers, the average will be the middle number. So, 260/5 = 52.

Step 2: Identify the smallest and largest numbers. Since 52 is the third number, the sequence is 48, 50, 52, 54, 56. So, the smallest number is 48 and the largest is 56.

Step 3: Calculate half the square of the smallest number. (48^2)/2 = 1152.

Step 4: Add the largest number to half the square of the smallest number. 1152 + 56 = 1208.

So, the sum of the largest number amongst them and half the square of the smallest number amongst them is 1208.